How to calculate an orthogonal plane from a vector

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I have a position in space called X1. X1 has a velocity called V1. I need to construct an orthogonal plane perpendicular to the velocity vector. The origin of the plane is X1.

I need to turn the two edges from the plane into two vectors, E1 and E2. The edges connect at the origin. So the three vectors form an axis

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Pick a vector W that is not aligned with V1. Now compute
E1 = cross_product(V1, W)
E2 = cross_product(V1, E1)

VoilÃ .

So the three vectors form an axis

That didn't make any sense. Edited by Ã�lvaro

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VoilÃ .

French spotted !

That didn't make any sense.

It's understandable, it's basically 3d coordinate system but he simplified by "axis".

Edited by Alundra

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Yeah thanks,.that should work. And I just found out how to find W with no issues.

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I have a position in space called X1. X1 has a velocity called V1. I need to construct an orthogonal plane perpendicular to the velocity vector. The origin of the plane is X1.

I need to turn the two edges from the plane into two vectors, E1 and E2. The edges connect at the origin. So the three vectors form an axis

The equation of plane is:

Ax + By + Cx + D = 0

vector n(A, B, C) is a vector orthogonal to the plane. If you want to construct a plane orthogonal to V1, the equation of the plane would be:

V1.x * x + V1.y * y + V1.z * z + D = 0

If this plane must contain X1 then you can find out D. Replacing x, y and z by X1 vector components you have:

V1.x * X1.x + V1.y * X1.y + V1.z * X1.z + D = 0

D = -(V1.x * X1.x + V1.y * X1.y + V1.z * X1.z)

or

D = -dot(V1, X1)

where dot is scalar product.

Edited by jlluengo

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