It seems if I have two try/catch blocks in a row in a function, the second one doesn't seem to catch anything. For example, this script:

void main() {
    try { throw ("1"); }
    catch { print ("Exception 1"); }

    try { throw ("2"); }
    catch { print ("Exception 2"); }

    try { throw ("3"); }
    catch { print ("Exception 3"); }
}

prints only this:

Exception 1
2

So the first exception is caught and handled correctly, and the second one aborts the script (which prints the aborting exception, in my case, so you see the "2").

Thanks!