Putting WndProc into a class?
Author
I cant get my program to compile if WndProc is in a class?
this line (setting up the window class)
wc.lpfnWndProc = WndProc;
causes this error
C:\Programming\Projects\msvc\OpenGL Helper Library\glh.cpp(151) : error C2440: ''='' : cannot convert from ''long (__stdcall glhs::*)(struct HWND__ *,unsigned int,unsigned int,long)'' to ''long (__stdcall *)(struct HWND__ *,unsigned int,unsigned int,long
Then the wndproc function and the function in your class are different in some way 
Someone else will give you a better answer below:
Someone else will give you a better answer below:
Then the wndproc function and the function in your class are different in some way
Someone else will give you a better answer below:
Someone else will give you a better answer below:
Author
well that worked, but now it acts like its not a member of the class.
It gives error on ever member variabe reference
I got a bypass to this problem, but makeing a dummy WndProc functions, and passing all its data to my WndProc class function.
LRESULT CALLBACK WndProc(HWND p_hwn,UINT p_msg,WPARAM p_wparam,LPARAM p_lparam) {
return glh.WProc(p_hwn, p_msg, p_wparam, p_lparam);
}
What sort of overhead would there be in something like this?
Edited by - Eber Kain on December 13, 2001 7:38:47 PM
It gives error on ever member variabe reference
I got a bypass to this problem, but makeing a dummy WndProc functions, and passing all its data to my WndProc class function.
LRESULT CALLBACK WndProc(HWND p_hwn,UINT p_msg,WPARAM p_wparam,LPARAM p_lparam) {
return glh.WProc(p_hwn, p_msg, p_wparam, p_lparam);
}
What sort of overhead would there be in something like this?
Edited by - Eber Kain on December 13, 2001 7:38:47 PM
WinProc inside a class?
How do I turn my message procedure into a member of a class?
Windows in a class(1)
Windows in a class(2)
That should be enough. All on this board, found by using "the leetle search button in the corner."
[ GDNet Start Here | GDNet FAQ | MS RTFM | STL | Google ]
Thanks to Kylotan for the idea!
How do I turn my message procedure into a member of a class?
Windows in a class(1)
Windows in a class(2)
That should be enough. All on this board, found by using "the leetle search button in the corner."
[ GDNet Start Here | GDNet FAQ | MS RTFM | STL | Google ]
Thanks to Kylotan for the idea!
This topic is closed to new replies.
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