Integers to strings.
Author
I thought I''d post this rather than expend my energy figuring this one out.
I''m trying to convert an integer to a "string" (character array).
I can convert characters to "strings" easily, simply because of the nature of the character array.
But when it comes to intergers, the integer gets converted to ascii or something.
I tried typecasting it, but that doesnt seem to solve my problem.
Heres a brief snippet of what im doing:
#include
char array[100];
int age = 24;
char sex = ''M'';
array[0] = sex;
array[1] = age;
array[2] = ''\0'';
string str(array);
// This will print out as "M" followed by a junk-character because of the mis-converted variable.
How can this be done???
Thanks.
~ I''''m a wannabe programmer ~
C: See itoa().
C++: See stringstream.
[ GDNet Start Here | GDNet FAQ | MS RTFM | STL | Google ]
Thanks to Kylotan for the idea!
C++: See stringstream.
[ GDNet Start Here | GDNet FAQ | MS RTFM | STL | Google ]
Thanks to Kylotan for the idea!
#include #include #include .int main(void){ std::stringstream sstrm; int i = 42; std::string str = "The meaning of life is "; sstrm << str << i << '\n'; std::cout << sstrm.str; std::cout.flush(); return 0;} [Edit: References]
I thought someone might also find these useful:
[DevX] Automating TypeConversions with stringstream Objects
[cplusplus.com] C++ reference: stringstream
[ GDNet Start Here | GDNet FAQ | MS RTFM | STL | Google ]
Thanks to Kylotan for the idea!
Edited by - Oluseyi on December 31, 2001 10:11:32 PM
if your not supposed to use a library function, you can write your own algorithm. im not goinu post it for you, but ill give you a hint:
if you want to get the rightmost digit,
int i = 1245;
int RightMost = i % 10;
now, you could put that in a char like this
char C = RightMost + '0'; //= '5'
!!
///sorry, its %, not mod!
Edited by - evilcrap on December 31, 2001 11:16:19 PM
if you want to get the rightmost digit,
int i = 1245;
int RightMost = i % 10;
now, you could put that in a char like this
char C = RightMost + '0'; //= '5'
!!
///sorry, its %, not mod!
Edited by - evilcrap on December 31, 2001 11:16:19 PM
I haven't checked the ASCII chart lately, but all digits in ASCII are just that digit plus 0x30. So in ASCII, 1 = 0x31, 2 = 0x32, etc. More accurately, '1' = 0x31, '2' = 0x32, etc. The 0x implies that the number is in hexadecimal form.
Edited by - masonium on December 31, 2001 11:13:05 PM
Edited by - masonium on December 31, 2001 11:13:05 PM
Author
Holy moly.
All this sounds like overkill to me.
There''s gotta be an easier way.
The strings I am using are the STL string.
So I guess I can create a regular array of char''s, then use sprintf to convert anything I need to an array, and then print them out.
- This method seems easier than all the previously posted stuff.
Or am i missing something?
~ I''''m a wannabe programmer ~
All this sounds like overkill to me.
There''s gotta be an easier way.
The strings I am using are the STL string.
So I guess I can create a regular array of char''s, then use sprintf to convert anything I need to an array, and then print them out.
- This method seems easier than all the previously posted stuff.
Or am i missing something?
~ I''''m a wannabe programmer ~
Hey.
I assume what you are trying to do is turn the int that has the value of 24 to a string reading "24"? If I am wrong just ignore this, but if I am correct, this should do the trick.
Hopefully that will work.
Minion
I assume what you are trying to do is turn the int that has the value of 24 to a string reading "24"? If I am wrong just ignore this, but if I am correct, this should do the trick.
char *temp[3];sprintf(temp, "%d", age); Hopefully that will work.
Minion
Not sure if this is right but try this
char Array[100];
sprintf(Array, "%c %d", sex, age);
%c would be character and %d should be the integer age
I don''t remember my C thingys for printf so you''ll have to find the right one for a character and a integer but thats how i would do it. Hope that helps somewhat
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Black Hole Productions
President/Programmer/Expert on stuff
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char Array[100];
sprintf(Array, "%c %d", sex, age);
%c would be character and %d should be the integer age
I don''t remember my C thingys for printf so you''ll have to find the right one for a character and a integer but thats how i would do it. Hope that helps somewhat
||--------------------------||
Black Hole Productions
President/Programmer/Expert on stuff
||--------------------------||
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