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# not sure how to go about doing this:

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OK, I have it worked out to look nice if ''size'' equals 12 or less, but higher than that and it comes onto the next line. So I want to make it so it only shows the last 12 numbers in the multiplicaiton tabke, say I put in 45 for ''size'' than I would want to show 34-45. I thought it might work if i subtraced ''a'' from ''size'' in the FOR staements, but I just eneded up with an infinite loop. any help? thanks!
  #include #include using namespace std; main() { int size; int x, int y; int a = size - 12; cout << endl<< "How many rows/columns would you like in your multiplication table? "; cin >> size; cout << endl; cout << size << " by " << size << "multiplication table" << endl << endl << " |"; for (x = 1; x <= size; x++) //column headers cout << setw(3) << x << " "; cout << endl; for (x = 1; x <= size; x++) //row headers cout << "______"; cout << endl; for (x = 1; x <= size; x++) { cout << endl; cout << setw(2) << x << setw(2) << "|"; for (y = 1; y <= size; y++) cout << setw(3) << x*y << " "; } cout << endl; return 0; } 
The Light shine on you

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anybody?

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You could try something like this:

int start;

if (size>12) //Only do the subtraction if it''s going to result in > 0
start = size-12;
else
start=1;

then in all your loops change it from x=1; to x=start; (and y=1; to y=start. That should solve your problem.

Billy - BillyB@mrsnj.com

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You can''t say "int a = size - 12", and expect a to be automagically calculated every time the value of size changes. C++ is a static language! You must put this calculation after getting size from the user. You will also want to check if a is less than a particular size and, if so, modify it to become a particular minimum size. For example:

  // untested codeconst int max_size = 12;const int min_size = 6;cin >> size;int a = size - max_size;if( a < min_size ) a = min_size;

Also, bear in mind that when you receive user input into a numeric field, the user might enter a non-numeric. You need to check the cin failbit for that, else your program will not do anything sensible in the face of invalid input.

--
1st law of programming: Any given program, when running, is obsolete.

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