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I have a matrix of 512*512 points (x,y,z) and i have to reconstitute the 3d object. i thought to do like this : for each four points which form a square decompose into 2 triangles but it makes 511*511*2=522242 triangles. Is-it possible to display all them in a quick time? (because i have to rotate, zoom,light, applicate a photo of the real object on... the 3d object) Is it better to display 1 square in the place of 2 triangles? Is there another best method? (but not filter the points which contain not enough information and then make a DELAUNAY triangulation because the delaunay triangulation takes too many time) thx for response.

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Drawing 522242 triangels per frame will kill your performance on just about every PC. Do you have to draw all of them? Have you considerd some kind of cullin. And you yust have to use at least VA (VAR or CVA even better)

There are more worlds than the one that you hold in your hand...

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quote:
Original post by ioda
Is it better to display 1 square in the place of 2 triangles?



I belive I''m correct in saying that if you setup a QUAD to be draw gfx drivers translate this into 2 triangles anyways, I belive this is related to gfx cards expecting the data in some kinda triangle format

(I could be wrong, as I''m sure someone will point out if I am, as I''m trying to remember from something I read a long while back, and things might have changed since then)

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