Author
Hello!!!
How can I print on the screen the __int 64 variable because the code like that:
#include.........
__int64 variable;
int main()
{
varaible=987654321987;
cout<>varaible;
}
but this dosen''t work.Why????
Thanx for answer and sorry for my Ugly english!!!!!!!
Sopek
Author
sorry for this seccond post.
in the last post I was made a mistake. In the code should be:
__int64 v;
main()
{
v=658564564573;
cout<}
in the last post I was made a mistake. In the code should be:
__int64 v;
main()
{
v=658564564573;
cout<}
quote:Original post by sopek
F..k what happened!!!??? I was wrote that "cout<Sory!!!
Yet another good reason to usewhitespacetoenhancereadability.
cout << v; The board doesn''t interpret this as an opening HTML tag. [ GDNet Start Here | GDNet Search Tool | GDNet FAQ | MS RTFM [MSDN] | SGI STL Docs | Google! ]
Thanks to Kylotan for the idea!
Use VS.NET, whose libraries have suitable overloads, or write overloads for the libraries you''re using at the moment.
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