Archived

This topic is now archived and is closed to further replies.

Quick math question

This topic is 6028 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

Recommended Posts

"1 = 1 = 2" ..wrong (unless you are in the modulo( 1 ) universe)

"1 = 1 = 1" ..right

(There is no border around this image)

Share on other sites
Seems a strange question so I''ll give a strange answer. x=1 is always true, while x==1 may or may not be true.

Share on other sites
An interesting related mathematics conundrum...

0 = 0
0 = 0 + 0 + 0 + 0 + 0 + 0 + ...
0 = (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + ...
0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...
0 = 1

How is this possible? The solution (as to why this isn''t true) is found in the study of infinite series.

Share on other sites
That doesn't require the study of infinite series to solve. The answer is that you're assuming that 1 - 1 + 1 - 1 + 1 - 1 + ... actually equals something, which it obviously does not.

Try this one:

"proof" that everything = everything

Let a be a number greater than b, and let c be the difference.

a = b + c
a(a - b) = (b + c)(a - b)
a2 - ab = ab + ac - b2 - bc
a2 - ab - ac = ab - b2 - bc
a(a - b - c) = b(a - b - c)
a = b

[edited by - Beer Hunter on March 23, 2002 6:16:45 PM]

Share on other sites
(a-b-c) is 0. Just because x*0 = 0 and y*0 = 0 doesn''t imply x = y.

Enough with the algebra games. Do some useful math.

Share on other sites
quote:
Original post by Beer Hunter
That doesn''t require the study of infinite series to solve. The answer is that you''re assuming that 1 - 1 + 1 - 1 + 1 - 1 + ... actually equals something, which it obviously does not.

Actually, it does equal something. "Obviously", the series:

(sigma from n=0 to infinity) (1-1) = 0 and
(sigma from n=0 to infinity) (0) = 0.

If you add x sets of 0 together you get 0 and
If you add x sets of (1 - 1) together you get 0.

I would think you would at least know that before taking 2nd/3rd (?) semester calculus.

Share on other sites
quote:
Original post by mnansgar
Actually, it does equal something. "Obviously", the series:

(sigma from n=0 to infinity) (1-1) = 0 and
(sigma from n=0 to infinity) (0) = 0.

And since when infinity times 0 = 0 ?

Share on other sites
quote:
Original post by pouya
And since when infinity times 0 = 0 ?

A sigma sign means to add, not multiply, if that''s what you''re getting at ...

(sigma n=0 to infinity) (n) is equivalent to (0 + 1 + 2 + 3 + ...).
(sigma n=0 to infinity) (1) is equivalent to (1 + 1 + 1 + 1 + ...).

Sorry if I misunderstood.

Share on other sites
Oh okay, I thought you means the sum of all those n''s, times zero.

(now if the damn slowass gamedev server would let me post this after the fifth time it timed out)

Share on other sites

This topic is 6028 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

This topic is now closed to further replies.

1. 1
2. 2
3. 3
4. 4
Rutin
14
5. 5

• 10
• 11
• 14
• 10
• 25
• Forum Statistics

• Total Topics
632651
• Total Posts
3007657
• Who's Online (See full list)

There are no registered users currently online

×