Archived

This topic is now archived and is closed to further replies.

Programmer One

Quick math question

Recommended Posts

"1 = 1 = 2" ..wrong (unless you are in the modulo( 1 ) universe)

"1 = 1 = 1" ..right


(There is no border around this image)

Share this post


Link to post
Share on other sites
An interesting related mathematics conundrum...

0 = 0
0 = 0 + 0 + 0 + 0 + 0 + 0 + ...
0 = (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + ...
0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...
0 = 1

How is this possible? The solution (as to why this isn''t true) is found in the study of infinite series.

Share this post


Link to post
Share on other sites
That doesn't require the study of infinite series to solve. The answer is that you're assuming that 1 - 1 + 1 - 1 + 1 - 1 + ... actually equals something, which it obviously does not.

Try this one:

"proof" that everything = everything

Let a be a number greater than b, and let c be the difference.

a = b + c
a(a - b) = (b + c)(a - b)
a2 - ab = ab + ac - b2 - bc
a2 - ab - ac = ab - b2 - bc
a(a - b - c) = b(a - b - c)
a = b

[edited by - Beer Hunter on March 23, 2002 6:16:45 PM]

Share this post


Link to post
Share on other sites
Guest Anonymous Poster
(a-b-c) is 0. Just because x*0 = 0 and y*0 = 0 doesn''t imply x = y.

Enough with the algebra games. Do some useful math.

Share this post


Link to post
Share on other sites
quote:
Original post by Beer Hunter
That doesn''t require the study of infinite series to solve. The answer is that you''re assuming that 1 - 1 + 1 - 1 + 1 - 1 + ... actually equals something, which it obviously does not.


Actually, it does equal something. "Obviously", the series:

(sigma from n=0 to infinity) (1-1) = 0 and
(sigma from n=0 to infinity) (0) = 0.

If you add x sets of 0 together you get 0 and
If you add x sets of (1 - 1) together you get 0.

I would think you would at least know that before taking 2nd/3rd (?) semester calculus.

Share this post


Link to post
Share on other sites
quote:
Original post by mnansgar
Actually, it does equal something. "Obviously", the series:

(sigma from n=0 to infinity) (1-1) = 0 and
(sigma from n=0 to infinity) (0) = 0.


And since when infinity times 0 = 0 ?

Share this post


Link to post
Share on other sites
quote:
Original post by pouya
And since when infinity times 0 = 0 ?


A sigma sign means to add, not multiply, if that''s what you''re getting at ...

(sigma n=0 to infinity) (n) is equivalent to (0 + 1 + 2 + 3 + ...).
(sigma n=0 to infinity) (1) is equivalent to (1 + 1 + 1 + 1 + ...).

Sorry if I misunderstood.

Share this post


Link to post
Share on other sites
Oh okay, I thought you means the sum of all those n''s, times zero.
My bad.

(now if the damn slowass gamedev server would let me post this after the fifth time it timed out)

Share this post


Link to post
Share on other sites
I have to wonder at the whole point of this thread! Unless someone can justify to me its relevance to Game Programming, I will close this thread and spare us all these pointless posts filled with erroneous divide by zero errors and bi-modal infinite series!

Timkin

Share this post


Link to post
Share on other sites
Since I have not seen any justification for keeping this thread open, I am going to close it due to it''s lack of relevance.

Timkin

Share this post


Link to post
Share on other sites
Guest
This topic is now closed to further replies.