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# Damage after Normal Block

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I get this when I make a ''new'' object of my own class and delete it. Now I have made my own destructor in that class but currently there is nothing in it, just empty braces. Here is the code which is in my ''main'' function: A* a = new A(blah blah); delete a; Where can I look up these Debug errors?

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I think I found the culprit. I keep an array of pointers in my class. In my constructor I define it's proper size, and also make each element point to NULL. Like so:
array[size];for(int i=0;i < size; i++){ array = NULL;}

Now when I comment out the for loop, I dont get the error anymore. Why is that? Am I going out of the array index?

[edited by - CoderX on May 31, 2002 1:09:22 PM]

[edited by - CoderX on May 31, 2002 1:10:08 PM]

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It''s probably just a matter of style, but I suggest using memset rather than looping through the array.

  #define SIZE 10void main(){  <datatype> *array = new <datatype>[SIZE];  memset(array,''\0'',SIZE*sizeof(<datatype>));  delete [] array;}

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You are right. It has to do with the way I implemented the array of pointers. I get a warning that I am making a zero-sized array, but which I define the size in the constructor, so I think this is bad programming and have ditched it.

So, now what I am doing is keeing just a pointer of type same class in my class. Then in the constructor, I want to make a new array of pointers of type same class. But the compiler now gives me an error that I have to define a default constructor for my class. Here is what I got in the class now:

class A{private:  A* arrayA;public: A(int size) {   arrayA = new A[size]; }}

Now I wrote a default constructor and it works. But is that okay? Why does the array definition need a default destructor? I know I am doing something stupid here.

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MEMORY LEAK
class A{private:  A* arrayA;public:   A(int size)  {    arrayA = new A[size];   }};

You need to do this:

class A{private:  A* arrayA;public:  A() : arrayA(NULL) {}  A(int size)  {    arrayA = new A[size];   }  ~A()  {    if(arrayA != NULL)      delete [] arrayA;  }};

You don't need to set the individual pointers to null before deleting them.

But you have to delete the array, or else every time your array gets destroyed, you'll leave a chunk of memory.

[edited by - daerid on May 31, 2002 6:48:20 PM]

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Thanks for the response. But I already have that in my class, just didn''t write it out in the post because it was irrelevant to my question.

I think I am getting the hang of this, but now I got another problem. I got this same class going and I also added a function that is supposed to add stuff to the array. Here is what I got in that function:

void A::addElement(A* newElement){	array[numberOfElements] = newElement;	numberOfElements++;};

This is me this error:

binary ''='' : no operator defined which takes a right-hand operand of type ''class A *'' (or there is no acceptable conversion)

What am I doing wrong now? Been trying to figure this out for a while.

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You need to overload the = operator for your class. Look it up on cplusplus.com. It means that the = operator for your class is not defined. You may need to write a copy construtor too (which is a good thing to have anyway).

/*=========================================*/
/* Chem0sh */
/* Lead Software Engineer & Tech Support */
/* http://www.eFaces.biz */
/*=========================================*/

[edited by - Chem0sh on May 31, 2002 7:10:01 PM]

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I suspected that but thought that this is just a simple assignment of addresses. Well I have overloaded that = operator and it works fine. Thanks for the help and for the awesome link as well.

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