Reading each char of a string
Author
Well say I had a char array something like:
char string[5] = "char";
how do I read each character out of the string?, so I seperate each character like: first I get the c then the h then the a then the r , thanks to anyone who can help me with this
( oh yeah I''m not using windows )
Cheers
Stealth
You just reference them like you would any Array.
i.e.
char string[5] = "char";
string[0] returns ''c''
string[1] returns ''h''
etc...
"I thought Genius lived in bottles..." - Patrick Star
i.e.
char string[5] = "char";
string[0] returns ''c''
string[1] returns ''h''
etc...
"I thought Genius lived in bottles..." - Patrick Star
I don't know if you want to do it in c or c++ but you can do this in c and basicly the same thing with cout in c++:
or with a for loop like this:
it's supposed to be string in there but it disappears when i post it because is used to italics on this board i guess.<img src="wink.gif" width=15 height=15 align=middle><br><br><SPAN CLASS=editedby>[edited by - Shenron on June 8, 2002 2:53:30 AM]</SPAN> </i>
char string[5] = "char";putchar(string[0]);putchar(string[1]);putchar(string[2]);putchar(string[3]); or with a for loop like this:
char string[5] = "char";int i;for(i = 0; i < 4; i++) putchar(string); it's supposed to be string in there but it disappears when i post it because is used to italics on this board i guess.<img src="wink.gif" width=15 height=15 align=middle><br><br><SPAN CLASS=editedby>[edited by - Shenron on June 8, 2002 2:53:30 AM]</SPAN> </i>
Shenron,
1) Ah, you go this now, as well
.
2) You fixed it
.
[edited by - Null and Void on June 8, 2002 3:02:33 AM]
1) Ah, you go this now, as well
.2) You fixed it
.[edited by - Null and Void on June 8, 2002 3:02:33 AM]
You can also use a pointer to access the character array. Like this:
char string[5] = "char";
char *charPtr = string; //Or char *charPtr = &string[0];
char theChar;
while( ((theChar = *charPtr++) != ''\0'' ) putchar( theChar );
Kory
char string[5] = "char";
char *charPtr = string; //Or char *charPtr = &string[0];
char theChar;
while( ((theChar = *charPtr++) != ''\0'' ) putchar( theChar );
Kory
Author
hey thanks for the replies but I THINK I figured it out I havent tried yet but I think I got the idea
thansk anyway
cheers
Stealth
thansk anyway
cheers
Stealth
Author
Ok I KINDA got it working except its now giving me the chars backwards, I mean if I go something like:
char string[7] = "string";
char *pchar = &string[3];
int main()
{
cout << pchar;
}
then it will print "ing" the last 3 letters of the string, I was wondering if there was way to read them from the start????, this is something I need to know since the strings I will be reading will be 256 chars long most probably and I dont wanna have to read thru all of them backwards to get to the start, OR maybe I should read them until I get a blank space, oh nah sorry I''m confusing u all lol I think I got it
char string[7] = "string";
char *pchar = &string[3];
int main()
{
cout << pchar;
}
then it will print "ing" the last 3 letters of the string, I was wondering if there was way to read them from the start????, this is something I need to know since the strings I will be reading will be 256 chars long most probably and I dont wanna have to read thru all of them backwards to get to the start, OR maybe I should read them until I get a blank space, oh nah sorry I''m confusing u all lol I think I got it
#include <iostream>using namespace std;int main(){ char string[7] = "string"; char *pchar = &string[0]; <--- HINT HINT cout << pchar << endl; return 0;}
Your pointer tells cout where the begining of the string is, the end is either zero terminated or NULL terminated (I forget which, NULL I think). So your setting the pointer to ''i'' and reading to the end.
To grab substrings and find chars in a string look at the string.h lib for some useful functions. (or use the STD string class).
,Jay
To grab substrings and find chars in a string look at the string.h lib for some useful functions. (or use the STD string class).
,Jay
cpp-style:
c-style::
for(int i=0;i<4;i++)cout<<<' '; c-style::
for(int i=0;i<4;i++)printf("%c ",string);<br> </pre> </font><br>i'm not sure about c-style, i compile in cpp! ;-) </i> <br>[edit] just put the between [ c o d e ] and [ / c o d e ]!<br>[edit] backwards huh?:<font color=red><br><pre><br>for(int i=6;i!=0;i–) //suppose u use string as sample now…<br>cout<<string<i><<' ';<br> </pre> </font><br><br><br><SPAN CLASS=editedby>[edited by - Pipo declown on June 8, 2002 10:47:45 AM]</SPAN> </i> This topic is closed to new replies.
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