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trapeze

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  1. Quote:Original post by Kazgoroth Probably neither of those. No one can give you a sensible response to that unless you tell us what your goals are however. something i will need to work in the industry. more specifically, computer networks, communications, telecommunications and whatnot.
  2. Quote:Original post by Promit Most likely neither. What languages do you already know? hm... matlab.. please don't laugh out loud... i do know a bit C/C++.
  3. i am thinking about learning even though i know very little of them. but, i don't know which is better ? by being better it may depend on my purposes. however, i would like to hear from others. thx.
  4. HI All Thx for your kindly help. I've got one quicky questoin. How can I check the return value of fread() ?
  5. Quote:For example, if this is the command string: d:/project/program.exe -foo1.raw -foo2.raw argc would equal 3, and argv would contain the following: argv[0] = "d:/project/program.exe" argv[1] = "-foo1.raw" argv[2] = "-foo2.raw" Spaces separate the parameters for programs. It is up to the program itself to decipher the meaning of each argument, or use tokens (such as -parm and /parm) I only type like programname foo1.raw foo2.raw and it works.
  6. The code is not long. I'm posting it here. ------------------------------------------------- #include <iostream> using namespace std; int main(int argc, char *argv[]) { FILE *file; int BytesPerPixel; int Size = 256; if (argc < 3) { cout << "usage: program_name input_image.raw output_image.raw[ [BytesPerPixel = 1] [Size = 256]" << endl; return 0; } if (argc < 4) { BytesPerPixel = 1; } else { BytesPerPixel = atoi(argv[3]); if (argc >= 5) { Size = atoi(argv[4]); } } unsigned char Imagedata[Size][Size][BytesPerPixel]; if (!(file=fopen(argv[1],"rb"))) { cout << "ERROR" << argv[1] <<endl; exit(1); } fread(Imagedata, sizeof(unsigned char), Size*Size*BytesPerPixel, file); fclose(file); if (!(file=fopen(argv[2],"wb"))) { cout << "ERROR" << argv[2] << endl; exit(1); } fwrite(Imagedata, sizeof(unsigned char), Size*Size*BytesPerPixel, file); fclose(file); return 0; } ------------------------------------------------------ This code just reads pic in and writes the same pic out. The problem is about the values stored in Imagedata...
  7. [quoteThen it sounds likely that the code path where the printing is done is not reached, or that the output stream is never flushed before end of execution. Perhaps try sending a std::flush to cout would help. Otherwise, post the relevant code.[/quote] Thx. you mean adding using std::flush; at the beginning ?
  8. Quote:Original post by Shuger If you can't use debugger, you can always display picture[0][0][0] as number instead of char THX ! But nothing showed up on my screen.
  9. Quote:Original post by grekster It could be that Picture[0][0][0] is storing a value that doesnt have a char representation to show when you pass it to cout. I cant remember exactly which values do or dont display something but IIRC the values from 0 to 15 roughly wont show anything. If you have a debugger try stepping through and manually check the memory at Picture[0][0][0]. THX !! I tried to debug but failed. I googled and tried what they said to debug with Dev but I couldn't make it...
  10. part of the code, reading an image file into memory -------------------------------------------------------- unsigned char Picture[Size][Size][BytesPerPixel]; if (!(file=fopen(argv[1],"rb"))) { cout << "Cannot open picture: " << argv[1] <<endl; exit(1); } fread(Picture, sizeof(unsigned char), Size*Size*BytesPerPixel, file); fclose(file); --------------------------------------------------------- when i tryied to get the value of the 1st element in Picture, i put cout << Picture[0][0][0] << endl; after fread(.... before flose(file); , it turned out to be nothing printed on my WinXP command prompt. However, the image file was stored successfully because i got the desired image after end of execution(store pic and spit out the exact same pic). the problem is i couldn't get the values stored in Picture. any ideas ? thx. ...racking my brain....
  11. THX guys ! That worked ! I guess I was dizzy since I've been C++ing for over 9 hrs.. and is still going..
  12. #include <iostream> using namespace std; int main() { int a[2][13] ={ {90, 23, 26, 31, 50, 71, 39, 31, 61, 80, 11, 20, 41}, {50, 31, 29, 31, 50, 31, 30, 61, 34, 70, 38, 90, 41}, }; cout << *a[2][8] <<endl; return 0; } ----------- my Dev-C++ says ... invalid type argument of `unary *' if i use cout << a[2][8] <<endl; , it says 207744 why is this ? plz help~~~~ thx.
  13. Quote:Original post by Feralrath std::fill(occurrence + 0, occurrence + 10, 0); Thx ! That worked !
  14. Quote:Original post by Antheus Quote:i don't know how to plot. i can't find the funtions. x-axis is 0-9,10-19,..,90-99. y-axis is the result above. What kind of graphics, or is it text-mode only? C++ has no concept of graphics, either at language, or standard library level. So you'll need to find some way to draw or represent the histogram graphically yourself, or use some third-party library. The simplest way is probably to use cout and print some symbol in shape of histogram. Quote:also, how can i generate zero array at once for occurrence w/o typing them out ? Use a for loop or std::fill. thx ! i believe i can figure out the "for loop" method. however, i've no ideas for "std::fill". what's this ?
  15. #include<iostream> using namespace std; int main() { int i; int j; int k; int occurrence[10]={0,0,0,0,0,0,0,0,0,0}; int data[10]={6,14,82,42,46,32,97,44,27,68}; for (j=0; j<10; j++) { for (i=0; i<10; i++) { if ((data[j] >= 10*i) && (data[j] < 10*i+9)) occurrence[i]++; } } cout << "occurrence # is "; for (k=0; k<10; k++) cout << occurrence[k]<<" "; } ---------------------------------------------------------- i don't know how to plot. i can't find the funtions. x-axis is 0-9,10-19,..,90-99. y-axis is the result above. also, how can i generate zero array at once for occurrence w/o typing them out ? great thx !