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Applying Look At matrix

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#1 Alejandro   Members   

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Posted 29 December 2011 - 04:19 PM

I'm developing a camera class on OpenGL in C++, I want to see the position and rotation that the camera has when using gluLookAt(), for this I'm using glm::lookAt() function, it retrieves a matrix 4x4 and then I multiply the current stack matrix with the one that was retrieve, and then I translate the camera to the position.

So my code looks like this

void camera::drawDebug()
{
    glm::mat4 res = glm::lookAt(eye, target, up);
    glMultMatrixf(&res[0][0]);
    glTranslatef(-eye.x, -eye.y, -eye.z);
    glutWireCube(1.5);
}

with this code I get the following image, considering that the red cube is at the center(0, 0, 0), and the wire cube is the camera, eye is (0, 5, 5), target is (0, 0, 0), up is (0, 1, 0)

Posted Image

As you can see it appears that the rotation is applied correctly but the translation is not correct. I'm doing -eye translation because of what it says on the documentation of glulookat.

...gluLookAt is equivalent to glMultMatrixf(M); glTranslated (-eyex, -eyey, -eyez);


Any ideas on how to fix the translation?

#2 SiCrane   Moderators   

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Posted 29 December 2011 - 04:27 PM

I'm not 100% sure, but it looks like you're applying the eye transform twice. glm::lookAt() should already include the eye transform.

#3 Alejandro   Members   

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Posted 29 December 2011 - 05:01 PM

I try it, still not there, it looks similar to previous result.

#4 Alejandro   Members   

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Posted 29 December 2011 - 09:41 PM

Solved, if I inverse the matrix I get the results that I expected, at the end the code is like the following

void camera::drawDebug()
{
    glm::mat4 res = glm::lookAt(eye, target, up);
    res = glm::inverse(res);
    glMultMatrixf(&res[0][0]);
    glTranslatef(-eye.x, -eye.y, -eye.z);
    glutWireCube(1.5);
}

Don't know exactly why this works.




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