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Posted 02 October 2001 - 02:41 AM
Posted 02 October 2001 - 06:44 AM
t = (-B + sqrt(B^{2} - 4AC)) / (2A)
or
t = (-B - sqrt(B^{2} - 4AC)) / (2A)
Posted 02 October 2001 - 10:01 AM
Posted 02 October 2001 - 01:07 PM
Posted 03 October 2001 - 07:39 AM
quote:
Original post by Beer Hunter
grhodes_at_work: If b^2 - 4ac is negative, there are no real solutions. Or was that question intended from a programming perspective?
Posted 03 October 2001 - 06:35 PM
Posted 04 October 2001 - 04:27 AM
quote:
Original post by Beer Hunter
An object starts from rest at position = 0, and accelerates forwards at 2m/s. At what time will it be at position = -1?
Posted 04 October 2001 - 12:30 PM
Posted 05 October 2001 - 09:43 AM
quote:
Original post by Beer Hunter
Which sort of systems? I've only looked at SHM and UCM in my physics class, and I don't think you can get complex results with those, except for invalid cases. Or am I looking in the wrong place?
F = m*a = m*(d^{2}s/dt^{2})
F = -k*s
-k*s = m*(d^{2}s/dt^{2})
s = A*exp(i*omega*t)
ds/dt = A*i*omega*exp(i*omega*t)
and
d^{2}s/dt^{2} = A*i^{2}*omega^{2}*exp(i*omega*t)
or, since i^{2} = -1,
d^{2}s/dt^{2} = -A*omega^{2}*exp(i*omega*t)
-k*A*exp(i*omega*t) = -m*A*omega^{2}*exp(i*omega*t)
-k = -m*omega^{2}
or
omega = sqrt(k/m)
s = A*exp(i*sqrt(k/m)*t)
exp(iX) = cos(X) + i*sin(X)
s = A*cos(omega*t) + i*A*sin(omega*t)
Posted 05 October 2001 - 01:36 PM
Posted 08 October 2001 - 09:30 AM
quote:
Original post by Beer Hunter
That... almost makes sense. The one thing that I don''t quite get is, why do we assume that:
s = A*exp(i*omega*t)
That sort of looks like we''re assuming that the answer will be in terms of sines or cosines...
Posted 08 October 2001 - 01:19 PM
Posted 09 October 2001 - 04:53 AM
Posted 09 October 2001 - 06:38 AM
quote:
Original post by silvren
Ok, this post is for graham rhodes (moderator):
I see that you have decided to close some threads that concerned homework problems. In my opinion, isn''t it better to let him/she and everyone else that has problems with this stuff to post their questions and IF someone wants to answer they could do so?
I mean, if you and everyone else thinks it''s a simple problem, then you don''t have to reply, and thus leave the thread unanswered. If someone has the time and wants to answer they could do so and everyone is happy, especially the poster (aj37 in this case).
I don''t know, but there might be a risk that the forum gets filled with such questions, but I don''t think so.
Anyway, that''s my humble opinion.
Posted 09 October 2001 - 07:40 AM
d^{2} x / dt^{2} = c^{2} * x
x = A * exp (c*t) + B * exp (-c*t)
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