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# hlsl normalize a float9 ?

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4 replies to this topic

### #1the dodger uk  Members

Posted 25 March 2013 - 03:23 AM

i have a  float  data[9];

i need to normalize this

but i tryed to do

data = normalize(data)

which it did not like  , because its an array ,

how would i  code this please

### #2claesson92  Members

Posted 25 March 2013 - 03:53 AM

Ehm, language?

### #3Postie  Members

Posted 25 March 2013 - 04:09 AM

What sort of data does the float[9] represent? Is it a 3x3 matrix? or perhaps 3 Vector3's?

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### #4TiagoCosta  Members

Posted 25 March 2013 - 04:12 AM

If data[9] is simply a 9 dimensional vector you can do it manually:

float z = 0;

for(int i = 0; i < 9; i++)
z += pow(data[i], 2);

z = sqrt(z);

for(int i = 0; i < 9; i++)
data[i] /= z; //Or use a temporary vector if "data" is in a constant buffer


If data[9] is a 3x3 matrix divide each value by the determinant.

Do you have to normalize it in the shaders? It would be faster do normalize it in the CPU and send to the shaders.

Edited by TiagoCosta, 25 March 2013 - 04:18 AM.

### #5Hodgman  Moderators

Posted 25 March 2013 - 05:05 AM

It depends on how you define 'normalize'. With regards to length, like Tiago posted, so their Pythagorean length is 1? With regards to weighting so they sum to 1?

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