C++ - freeing dynamic memory

Shayel · 2013-04-27T20:36:34

Hello, I was wondering about freeing the dynamic memory, when the pointer is returned by the function. Let's say I have some piece of code: int* allocate() { int* ptr=new int[10]; return ptr; } int main() { int* myPointer=allocate(); delete [] myPointer; return 0; } Is this ok? I mean, is freeing the memory outside the function ok? It doesn't return exactly the same pointer, but when using "return" it creates a copy of the object, and the returns the copy.. am I correct? So myPointer points on the same place in the memory, even if it isn't "ptr". Another example: int* ptr1=NULL, ptr2=NULL, ptr3=NULL, ptr4=NULL; ptr1=new int; ptr2=ptr1; ptr3=ptr2; ptr4=ptr3; delete ptr4; Am I freeing ptr1-3, when freeing ptr4?

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Started by Shayel April 24, 2013 02:09 PM

19 comments, last by Khatharr 10 years, 11 months ago

Khatharr

8,814

April 27, 2013 08:36 PM

Am I freeing ptr1-3, when freeing ptr4?

From what I read in C++ Primer Plus this wouldn't work since ptr2,ptr3, and ptr4 are not considered pointers but ordinary int variables, the statement would have to be:
int* ptr1 = NULL, *ptr2 = NULL, *ptr3 = Null, etc...

Aye. Although if we ignore that then the answer is still no:

You don't delete pointers. You delete allocations.

Also:

[attachment=15341:pointing-to-god-1.jpg]

void hurrrrrrrr() {__asm sub [ebp+4],5;}

There are ten kinds of people in this world: those who understand binary and those who don't.

C++ - freeing dynamic memory

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C++ - freeing dynamic memory

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