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getting the RGB-values from a 16-bit pixel
Author
Hi
let''s say my pixel is stored in "unsigned short pixel"
and I want the value for red, green, blue separatly, how can I do that ??
THX in advance
Stefan Thomas
FS Productions
You mean unsigned short, right? 
Here''s how you''d do it:
Not sure about where you get the RGB values.
The road to success is always under construction
Here''s how you''d do it:
LPDIRECTDRAWSURFACE7 dds; // Our surfaceint lpitch; // Will hold the pitch for usDDSURFACEDESC2 ddsd; // The surface descriptionunsigned short Color;unsigned short *surface; // This will hold our surfaceint red,green,blue; // red, green and blue values// Let''s lock the surfacememset(&ddsd,0,sizeof(ddsd));ddsd.dwSize = sizeof(ddsd);dds->Lock(NULL,&ddsd,DDLOCK_SURFACEMEMORYPTR | DDLOCK_WAIT,NULL);lpitch = ddsd.lPitch>>1;surface = (unsigned short *)ddsd.lpSurface; // Get a pointer to the surfaceint x=50; // the x of the pixelint y=60; // the y of the pixelColor = (unsigned short)surface[x+y*lpitch]; // get the pixel// Get the valuesred = Color >> 11;green = Color >> 5;blue = Color << 11;dds->Unlock(); Not sure about where you get the RGB values.
The road to success is always under construction
Don''t forget there''s besides 565 also a 555 pixel format!
Instead of 6 bits, green has only 5 bits for its value.
Red moves one bit lower.
QTheBrain
Instead of 6 bits, green has only 5 bits for its value.
Red moves one bit lower.
QTheBrain
I''m not sure what I wrote will work...
This will work for sure:
red = (Color & 0xF800) >> 11;
green = (Color & 0x07E0) >> 6;
blue = Color & 0x001F;
Remember, This will only work for 565
The road to success is always under construction
This will work for sure:
red = (Color & 0xF800) >> 11;
green = (Color & 0x07E0) >> 6;
blue = Color & 0x001F;
Remember, This will only work for 565
The road to success is always under construction
This topic is closed to new replies.
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