Copying arrays
Author
hello-
i am trying to copy a char array into another char array. Is this possible just by assignment, or do i have to loop though and copy each value? Right now i am looping through, but i would prefer not to do that....
Thanks!
You can''t do it just by assignment.
However, you can do it using a call to memcpy() or if you know it is a nullterminated string you can use strcpy().
However, you can do it using a call to memcpy() or if you know it is a nullterminated string you can use strcpy().
By assigning a char array to another you copy the pointers to the array only, meaning the change you do in the first will occur in the other.
I suggest you read up on pointers before trying to copy arrays at all.
-----------------------------
Final Frontier Trader
I suggest you read up on pointers before trying to copy arrays at all.
-----------------------------
Final Frontier Trader
an array of characters can be copied using the
strcpy function.
char *1="This is a string";
char *2;
strcpy(2,1);
or
char string[80];
strcpy( string, "Another example " );
or
char string[80];
char string2[]="This is another string";
strcpy( string, string2 );
I do agree that if you want to learn c++ at some time you need to learn about pointers, but why if a person asks for a function to copy character arrays do you tell him to learn about pointers?
strcpy function.
char *1="This is a string";
char *2;
strcpy(2,1);
or
char string[80];
strcpy( string, "Another example " );
or
char string[80];
char string2[]="This is another string";
strcpy( string, string2 );
I do agree that if you want to learn c++ at some time you need to learn about pointers, but why if a person asks for a function to copy character arrays do you tell him to learn about pointers?
also
char string1[]="This is a string";
char* string2;
string2=string1;
is acceptable, and will copy by operator.
BUT char string2[20];will not copy directly by the operator, because the arrays are of different size.
char string1[]="This is a string";
char* string2;
string2=string1;
is acceptable, and will copy by operator.
BUT char string2[20];will not copy directly by the operator, because the arrays are of different size.
quote:Original post by RhoneRanger
I do agree that if you want to learn c++ at some time you need to learn about pointers, but why if a person asks for a function to copy character arrays do you tell him to learn about pointers?
So that he doesn''t do things like this:
quote:Original post by RhoneRanger
char *1="This is a string";
char *2;
strcpy(2,1);
And give himself a harder time than necessary
. 
quote:
char string1[]="This is a string";
char* string2;
string2=string1;
Is char* string2; a pointer? If so what kind of pointer?
By the way does anyone know a good place that tells you all about pointers? I have a learn C in 24 hours book and I understand every concept it has about pointers but it doesnt seem to be enough to understand more complex uses of pointers.
I searched with Google.. for example try this:
http://www.codeproject.com/useritems/PointerPrelude.asp
and if you want a book about c/c++ I suggest you the ONLY ONE: the Stroustrup!
Regards.
Fire burn wisdom in me,
Wisdom set mind and spirit free,
Moonlight shows me the mysteries of life,
Winternight gives me clearsight and storms to fight.
http://www.codeproject.com/useritems/PointerPrelude.asp
and if you want a book about c/c++ I suggest you the ONLY ONE: the Stroustrup!
Regards.
Fire burn wisdom in me,
Wisdom set mind and spirit free,
Moonlight shows me the mysteries of life,
Winternight gives me clearsight and storms to fight.
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