so how to pass char[32] as func param? i mean char p[32];

void func(char * param); doesnt seem to work when used like func(p); or func(&p);

i rather not to have func(char param[32]); thats the main reason i ask

original function had two parameters i didint set that second one that gave me the error but was a strange error related to char * thing, i reported the post already but there were some issues with server ill try to report this post again

The syntax for array passing is crazy in C++ but this will do allow you to do this:

template <size_t charCount>
void stringCopy(char (&output)[charCount], const char* source)
{
}

I highly recommend you use a template on the array parameter here because this function now works with any sized arrays.

ok so

inline int find_object_index(char * a, int len)
{


for (int i=0; i < OBJECT_LIST.len; i++)
if (nameIsEqual(a, OBJECT_LIST.container[i]->lname, len)) return i;


return -1;//not found
}

int obji = find_object_index(object[i].lname, 32);

where char lname[32];

didin't add , 32 as second parameter... end of story ;x

Or you could just a std::string and avoid the hassle :)

Have you considered std::array<type, N>?

The main advantage is that it contains its own length and you can use it in range-for.

Unfortunately, being an owning object it causes you to shuffle memory around... the template version sort of solves the problem but I'm personally not a fan of that syntax.

Note: it is a very different thing from std::string.

Have you considered std::array<type, N>?

The main advantage is that it contains its own length and you can use it in range-for.

Unfortunately, being an owning object it causes you to shuffle memory around... the template version sort of solves the problem but I'm personally not a fan of that syntax.

Note: it is a very different thing from std::string.

I agree the syntax for passing an array in C++ is crazy, the template only makes it so you can pass any size instead of for a fixed sized version of that function.