Rounding
Author
Could anyone tell me a function that would let me round a number to the nearest 25. I''m using Dev c++ if that makes a differnce.
Thanks in advance.
Author
No that isn't what I mean. For example if the user enters a 28 the will automatically be rounded down to 25, if the user enters 46 it is rounded up to 50. I need a function to do this automatically so that the program can process it depending on what value the user inputs.
Thanks.
[edited by - ank2 on April 23, 2002 4:18:25 PM]
Thanks.
[edited by - ank2 on April 23, 2002 4:18:25 PM]
Author
Thanks but i'm using C. I tried translating it but I can't. Is there a similar way to do this in C? Is there a similar function to the Round function you showed for C?
[edited by - ank2 on April 23, 2002 4:48:03 PM]
[edited by - ank2 on April 23, 2002 4:48:03 PM]
Well, I don''t know that C++ has a round() function, but to translate that code, it''s like this:
float RoundTo25(double d)
{
return (Round(d/25))*25;
}
If thispost = 0 Then
GoBack()
Else
Read()
End If
float RoundTo25(double d)
{
return (Round(d/25))*25;
}
If thispost = 0 Then
GoBack()
Else
Read()
End If
Try something like this:
int RoundTo25(int num){int round = num%25;if(round > 12)num += (25-round);else num -= round;return num;}
Doesn''t anyone test the code they post?
roundTo( 25, 0 ) == 0
roundTo( 25, 25 ) == 25
roundTo( 25, 26 ) == 25
roundTo( 25, 44 ) == 50
roundTo( 25, 1234 ) == 1225
etc.
int roundTo( int iTarget, int iSource ){ return( ( ( iSource + ( iTarget / 2 ) ) / iTarget ) * iTarget );} roundTo( 25, 0 ) == 0
roundTo( 25, 25 ) == 25
roundTo( 25, 26 ) == 25
roundTo( 25, 44 ) == 50
roundTo( 25, 1234 ) == 1225
etc.
ya. the other ones were wrong.
it''s just, as the guy said above:
rounded = int((num + .5 )) / 25 * 25
it''s just, as the guy said above:
rounded = int((num + .5 )) / 25 * 25
.
This topic is closed to new replies.
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