Complex number question! (not too hard, though)
Author
What say would (2 + 3i) * (2 + 3i) be?
i is the square root of -1 of course.
Thanks!!!
return Neff; //God bless gamedev!
quote:Original post by Neff
What say would (2 + 3i) * (2 + 3i) be?
i is the square root of -1 of course.
Thanks!!!
return Neff; //God bless gamedev!
(2 + 3i) * (2 + 3i)
(2 + 3i)^2
4+9i^2+12i
4-9+12i
-> 12i-5
It should be that I think... (i*i = -1)
Joakim Asplund
http://megajocke.cjb.net
quote:Original post by megajocke
12i-5
Not to be overly picky, but that should be written: -5+12i
(Looks correct to me)quote:Original post by Thunder_Hawk
Not to be overly picky, but that should be written: -5+12i
Ok... :-)
And Gamedev's forum seems to have some weird bug with quoting a message which contains a quote...
Joakim Asplund
http://megajocke.y2.org
[edited by - megajocke on November 9, 2002 6:21:16 PM]
Author
yay, that's the right answer! Thanks!!!
return Neff;
[edited by - neff on November 9, 2002 6:23:23 PM]
return Neff;
[edited by - neff on November 9, 2002 6:23:23 PM]
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