10 Random Numbers (C#)
Author
This is what I want to do basically create a slot machine. I have writen what operations I want to do. Would anybody be so kind to translate this to the c# language?
Generate 5 random numbers
if number = 1 then print on screen "bar"
if number = 2 then print on screen "apple"
if number = 3 then print on screen "cherry"
if number = 4 then print on screen "grapes"
if number = 5 then print on screen "lemon"
Thanks again,
Robert
Random rnd = new Random();
for (int i=0; i<5; i++) {
int number = rnd.Next(5) + 1;
switch (number) {
case 1:
Console.WriteLine("bar");
break;
case 2:
Console.WriteLine("apple");
break;
case 3:
Console.WriteLine("cherry");
break;
case 4:
Console.WriteLine("grapes");
break;
case 5:
Console.WriteLine("lemon");
break;
}
}
for (int i=0; i<5; i++) {
int number = rnd.Next(5) + 1;
switch (number) {
case 1:
Console.WriteLine("bar");
break;
case 2:
Console.WriteLine("apple");
break;
case 3:
Console.WriteLine("cherry");
break;
case 4:
Console.WriteLine("grapes");
break;
case 5:
Console.WriteLine("lemon");
break;
}
}
string[] slots = new string[]{ "bar", "apple", "cherry", "grapes", "lemon" };Random rnd = new Random();for( int i = 0; i < 5; i++ ) Console.WriteLine( slots[ rnd.Next(5) ] )--
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Author
How would i add a basic add up code?
[STAThread]
static void Main(string[] args)
{
Random rnd = new Random();
for (int i=0; i<3; i++) // going to print a total of 3 items
{
int number = rnd.Next(5) + 1; //go through all 5 cases
switch (number)
{
case 1: // if the number = case 1 then print ''BAR''
Console.WriteLine("BAR");
break;
case 2: // if the number = case 2 then print ''APPPLE''
Console.WriteLine("APPLE");
break;
case 3: // if the number = case 3 then print ''CHERRY''
Console.WriteLine("CHERRY");
break;
case 4: // if the number = case 4 then print ''GRAPES''
Console.WriteLine("GRAPES");
break;
case 5: // if the number = case 5 then print ''LEMON''
Console.WriteLine("LEMON");
break;
}
}
{
// Check to see if the user has won anything!
}
thank you,
rob
[STAThread]
static void Main(string[] args)
{
Random rnd = new Random();
for (int i=0; i<3; i++) // going to print a total of 3 items
{
int number = rnd.Next(5) + 1; //go through all 5 cases
switch (number)
{
case 1: // if the number = case 1 then print ''BAR''
Console.WriteLine("BAR");
break;
case 2: // if the number = case 2 then print ''APPPLE''
Console.WriteLine("APPLE");
break;
case 3: // if the number = case 3 then print ''CHERRY''
Console.WriteLine("CHERRY");
break;
case 4: // if the number = case 4 then print ''GRAPES''
Console.WriteLine("GRAPES");
break;
case 5: // if the number = case 5 then print ''LEMON''
Console.WriteLine("LEMON");
break;
}
}
{
// Check to see if the user has won anything!
}
thank you,
rob
"How would i add a basic add up code?"
What do you mean?
"int number = rnd.Next(5) + 1;"
int number = rnd.Next(1, 6);
What do you mean?
"int number = rnd.Next(5) + 1;"
int number = rnd.Next(1, 6);
Author
I mean if you get:
3 cherrys in a row add 20
and so on. Just as a basic example.
Thanks,
Rob
3 cherrys in a row add 20
and so on. Just as a basic example.
Thanks,
Rob
This is c code, i suppose it also works in c# as is:
[edited by - Nik02 on September 25, 2003 9:39:42 AM]
const int cherry = 4; //or some other number :)if ((slots[0]==cherry) && (slots[1]==cherry) && (slots[2]==cherry))Score += 20; [edited by - Nik02 on September 25, 2003 9:39:42 AM]
Meh, best way:
enum Slots {Bar, Cherry, Apple, Grapes, Lemon};
Random rand = new Random();
for (int i = 0; i < 5; i++)
Console.Out.WriteLine("{0}",(Slots)rand.Next(4));
enum Slots {Bar, Cherry, Apple, Grapes, Lemon};
Random rand = new Random();
for (int i = 0; i < 5; i++)
Console.Out.WriteLine("{0}",(Slots)rand.Next(4));
This topic is closed to new replies.
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