points[i++] = i++;
) in C++ (i.e. what autoincrement is done first)?
"Yeah, I would''ve killed you, but I''m glad I didn''t - the paperwork is a bitch"
points [i++] = i;points [i] = i++;i = i++;quote:Original post by Nervo
Any lvalue begin referenced more than once in any expression will be undefined behavior.
quote:Original post by chachaquote:Original post by Nervo
Any lvalue begin referenced more than once in any expression will be undefined behavior.
Not true at all.
quote:Original post by Nervo
well, I was stating that more as a question for someone to confirm it...just to be sure though, I meant being referenced more than once from both sides of the expression. Show me an example if you can exhibiting right and wrong then please.
EDIT: What I said before has too many holes in it...what is meant apparently is that an lvalue that is changed and then assigned back to it will be undefined i.e. the behavior will not be uniform across all implementations.
Except where noted, the order of evaluation of operands of individual operators and subexpressions of indi-vidualexpressions, and the order in which side effects take place, is unspecified.53) Between the previousand next sequence point a scalar object shall have its stored value modified at most once by the evaluationof an expression. Furthermore, the prior value shall be accessed only to determine the value to be stored.The requirements of this paragraph shall be met for each allowable ordering of the subexpressions of a fullexpression; otherwise the behavior is undefined. [Example:i = v[i++]; // the behavior is unspecifiedi = 7, i++, i++; // i becomes 9i = ++i + 1; // the behavior is unspecifiedi = i + 1; // the value of i is incremented—end example] 
