Void as a function parameter

ETFBlade · 2004-02-07T15:39:58

I have a question about syntax. Say you have a function void foo( struct a, int b, int c). Where: struct a{ int z, y;}; And where: void foo ( struct a, int b, int c){ a.z = b; a.y = c; } Now, I want to overload this function''s definition so that it can take either a,b,c, just a and b, just a and c, or just a as parameters. (I.e. foo( a, b, c,)... foo( a, c ).... foo ( a ,b)... ) My question is thus: With creating a declaration for a function that takes two out of three parameters, (i.e. foo( a, ,c)), where you need to be sure that the one int parameter you are using is the the third one so that it can be assigned properly, how would you create it so that the middle parameter of foo takes void. I know syntactically you can''t just enter void as the parameter, but I think there is a way to do it. (i.e. for loops can run without the first parameter defined )