Im building a program for tommorrow in my computer class. Could someone tell me how to make my first number greater than my second number? Here is the source code so far. #include <iostream> #include <conio.h> #include <stdio.h> #include <time.h> #include <stdlib.h> using namespace std; main() { int num1, num2; char op; int i, ans, guess; int b; for (b=1; b<=3; b++) { srand(time(NULL)); for (i=1; i <=1; i++) { num1 = rand()%12; } int c; for (c=1; c <=1; c++) { ; num2 = rand()%12; } switch(rand()%4) { case 0: op = '+'; ans = num1 + num2; break; case 1: op = '-'; ans = num1 - num2; break; case 2: op = 'x'; ans = num1 * num2; break; case 3: op = '/'; ans = num1 / num2; break; } cout << num1 << endl << op <<" " << num2 << endl <<"__________" << endl << "Press enter once, then answer the question: "; getch(); cin >> guess; if(ans == guess) { cout << "Good Job" << endl; } else if(ans) { cout << "Wrong!" << endl; } getch(); } return 0; }

Also, could someone tell me a way to output number correct vs. number wrong?

I don't understand the point in the for() loops... You could just do this:


EDIT:
For outputing the answers:
cout << "Correct answer: " << ans << endl;
cout << "Your guess: " << guess << endl;
Or whatever you want to combine the 2 lines.

I took out the second and third loops. Donno why I had them. The first one is to loop the program multiple times. And I tried what you said and it still didnt work.

Define "doesn't work". If you used the code I provided, then num1 will always be greater than or equal to num2. Or were you talking about outputting the right and wrong answers?

Nah, I just wanted to be able to output the number of answers correct vs. number of answers wrong, cause im gonna loop it ~25 times. So say you got 20 out of 25 correct, then it will show you got 20 correct, 5 wrong, 25 questions total, then %right.