Result =
ai*2^0 + aj*2^1 + ak*2^2 + al*2^3 + am*2^4 + an*2^5+ ao*2^5 + ap*2^7 +
bi*2^1 + bj*2^2 + bk*2^3 + bl*2^4 + bm*2^5 + bn*2^6+ bo*2^7 +
ci*2^2 + cj*2^3 + ck*2^4 + cl*2^5 + cm*2^6 + cn*2^7 +
di*2^3 + dj*2^4 + dk*2^5 + dl*2^6 + dm*2^7 +
ei*2^4 + ej*2^5 + ek*2^6 + el*2^7 +
fi*2^5 + fj*2^6 + fk*2^7 +
gi*2^6 + gj*2^7
Problem, how do i handle overflow?
For eg. ap + bo + cn + ddm + el + fk + gj> what if there all one?
From,
Nice coder
Binary method for calculating hardware/Software mults/divs.
My problem is that this is a hardware multiplication unit, so i end up with a little bit of a problem.
I end up with a bit of a bit-counting and adding problem... [bawling]
From,
Nice coder
I end up with a bit of a bit-counting and adding problem... [bawling]
From,
Nice coder
i posted Lord Clickster of Clicksters into some of your threads, where you asked about adders. On bottom of that page are << and >> , and next is exactly about multiplication. Interactive diagram.
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