Big to little
Author
//This seems to work
It converts a big inedian 32 bit int to Little inedian 32 bit int...
but if someone can make sure that it works, that would be good.
void BI2LI(int &data)
{
data = (((data>>28)&0xF)<<4) + ((data>>24)&0xF) + (((data>>20)&0xF)<<12) + (((data>>16)&0xF)<<8)
+ (((data>>4)&0xF)<<28) + (((data)&0xF)<<24) + (((data>>8)&0xF)<<16) + (((data>>12)&0xF)<<20);
}
Shouldn't it be something like this:
Can't varify that at the moment tho'.
data = ((data & 0xff000000) >> 24) | // Leftmost -> rightmost ((data & 0xff0000) >> 8) | // Middle-left -> middle-right ((data & 0xff00) << 8) | // Middle-right -> middle-left ((data & 0xff) << 24); // Rightmost -> leftmostCan't varify that at the moment tho'.
or perhaps this is conceptually cleaner:
void swap(int value){int temp = value;for (int i = 0; i < 4; i++){((char *)&value) = ((char *)&temp)[3-i];}}
I'd rather just not worry about what endian-ness I'm on, and use the host-to-network conversion functions. (network byte order is big endian)
Host to Network Short: htons()
Host to Network Long: htonl()
Network to Host Short: ntohs()
Network to Host Long: ntohl()
No further work needed, it's portable, and should be optimized accoring to your vendor's tastes.
Host to Network Short: htons()
Host to Network Long: htonl()
Network to Host Short: ntohs()
Network to Host Long: ntohl()
No further work needed, it's portable, and should be optimized accoring to your vendor's tastes.
And leaves you unprepared when you're given input from a file format defined to be little endian when you're on a big endian machine. ex: a UTF-16LE encoded file.
Quote:Original post by programwizardWikipedia on Endianness
Sorry to interrupt, but what's endian?
On Holy Wars and a Plea for Peace
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