/**$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*$
$*% PROGRAMMER NAME: BRANDON WALL *$%
%*$ DATE: 4-19-06 %*$
*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$**/
// Shimmer Inc. DataBase
#include <string>
#include <iostream>
#include <windows.h>
using namespace std;
int menu()
{
//Gets user's user name
int createAccount = 0;
{
cout << "\t\t\t+ Welcome to Shimmers Inc. +\n\n"
<< "***************************************************\n"
<< "** **\n"
<< "** Navigation: **\n"
<< "** 1) Create New Shimmer Account **\n"
<< "** 2) Log In With Existing Shimmer Account **\n"
<< "** 3) Exit **\n"
<< "** **\n"
<< "***************************************************\n\n"
<< "Please Make Your Selection: ";
cin >> createAccount;
}
}
int main(int createAccount)
{
//Declaire Variables
string userName;
string password;
string name;
string email;
string logName;
string logPass;
//Declaires the menu function
menu();
if(createAccount == 1)
{
//Clears screen for users info
system("cls");
//username
//Gets users new account info
cout << "1) Please enter Your New Username (One Word): ";
cin >> userName;
//password
cout << "\n2) Please enter Your Account Pssword: ";
cin >> password;
//name
cout << "\n\nFirst Name: ";
cin >> name;
//email
cout << "\nEmail Address: ";
cin >> email;
//Thank you ending
cout << "\nThank You.";
Sleep(2000);
//clear screen for loading message
system("cls");
//Loading message
cout << "\t\t\t\tL";
Sleep(1000);
cout << "O";
Sleep(1000);
cout << "A";
Sleep(1000);
cout << "D";
Sleep(1000);
cout << "I";
Sleep(1000);
cout << "N";
Sleep(1000);
cout << "G\n\n";
Sleep(2000);
//Waits for user to cont.
system("cls");
//Gives final Summary
cout << "Thank Your for Choosing Shimmer!\n"
<< "Heres Your Account Info: \n\n"
<< "Account Name: "
<< userName
<< "\nPassword: "
<< password
<< "\n\nPlease Write your Account Information Down Incase you Forget.\n\n"
<< "Please Log In when you are Transfered to the Menu.\n\n\n";
system("pause");
system("cls");
menu();
}
else if(createAccount == 2)
{
//Tells user to enter their account name
cout << "Account Name: ";
cin >> logName;
//Tells user to enter their account password
cout << "Password: ";
cin >> logPass;
if(logName != userName && logPass != password)
{
cout << "\n\nAccess Denied.";
//Delays for another try
Sleep(1000);
menu();
}
else if(logName == userName && logPass == password)
{
cout << "Welcome\n\n";
//waits for user to exit
system("pause");
}
}
else if(createAccount == 3)
{
cout << "\n\nOk, Bye.\n\n";
system("pause");
}
else
{
cout << "\n\nThats not an Option. Bye\n\n";
system("pause");
}
return 0;
}
[SOLVED] I have no idea...
Author
Hello, I was creating a little DataBase kind of Program, but it seems I've ran into a problem. When I select an option from the menu, no matter what i select, it does the samething, it creates a new account. Please help.
[Edited by - NUCLEAR RABBIT on April 20, 2006 10:49:03 AM]
This shouldn't compile as posted.
You are not returning anything from menu() and createAccount is not declared in main() (but you use it).
You should get an error about createAccount on the first if statement in the main function about it not being declared. You should also get, either a warning or an error about menu not returning anything.
That should solve your issue(s).
Edit: Just noticed, main should be:
int main()
{
}
As a minimum.
You are not returning anything from menu() and createAccount is not declared in main() (but you use it).
You should get an error about createAccount on the first if statement in the main function about it not being declared. You should also get, either a warning or an error about menu not returning anything.
That should solve your issue(s).
Edit: Just noticed, main should be:
int main()
{
}
As a minimum.
You make createAccount a local variable in menu(). So it disappears after the function is over.
Also, main() shouldn't take "int createAccount" as a parameter.
Instead, create a variable in the main() method called "createAccount", and have "menu" return the int choice (return createAccount;)
Good luck!
Also, main() shouldn't take "int createAccount" as a parameter.
Instead, create a variable in the main() method called "createAccount", and have "menu" return the int choice (return createAccount;)
Good luck!
Hi bud,
Right so i have got it working here for you:
You have quite alot of issues here though.
1. The C++ standard says that main should take 1 of two forms:
int main();
or
int main( int argc, char* argv[] );
2. When the menu is selected and the creation of the account is made, for example, the menu is reshown but when you select it the application exits. To keep this application alive you need to do some sort of looping, until a certain option is chosen to exit the application.
3. The formatting of the code is pretty bad, but thats not so important.
I hope that helps mate,
Dave
Right so i have got it working here for you:
/**$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*$$*% PROGRAMMER NAME: BRANDON WALL *$%%*$ DATE: 4-19-06 %*$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$*%$**/ // Shimmer Inc. DataBase#include <string>#include <iostream>#include <windows.h>using namespace std;void menu( int& output ){ cout << "\t\t\t+ Welcome to Shimmers Inc. +\n\n" << "***************************************************\n" << "** **\n" << "** Navigation: **\n" << "** 1) Create New Shimmer Account **\n" << "** 2) Log In With Existing Shimmer Account **\n" << "** 3) Exit **\n" << "** **\n" << "***************************************************\n\n" << "Please Make Your Selection: "; cin >> output;}int main(int createAccount){ int menuSelection = 0; //Declaire Variables string userName; string password; string name; string email; string logName; string logPass; //Declaires the menu function menu(menuSelection); if(menuSelection == 1) { //Clears screen for users info system("cls"); //username //Gets users new account info cout << "1) Please enter Your New Username (One Word): "; cin >> userName; //password cout << "\n2) Please enter Your Account Pssword: "; cin >> password; //name cout << "\n\nFirst Name: "; cin >> name; //email cout << "\nEmail Address: "; cin >> email; //Thank you ending cout << "\nThank You."; Sleep(2000); //clear screen for loading message system("cls"); //Loading message cout << "\t\t\t\tL"; Sleep(1000); cout << "O"; Sleep(1000); cout << "A"; Sleep(1000); cout << "D"; Sleep(1000); cout << "I"; Sleep(1000); cout << "N"; Sleep(1000); cout << "G\n\n"; Sleep(2000); //Waits for user to cont. system("cls"); //Gives final Summary cout << "Thank Your for Choosing Shimmer!\n" << "Heres Your Account Info: \n\n" << "Account Name: " << userName << "\nPassword: " << password << "\n\nPlease Write your Account Information Down Incase you Forget.\n\n" << "Please Log In when you are Transfered to the Menu.\n\n\n"; system("pause"); system("cls"); menu(menuSelection); } else if(menuSelection == 2) { //Tells user to enter their account name cout << "Account Name: "; cin >> logName; //Tells user to enter their account password cout << "Password: "; cin >> logPass; if(logName != userName && logPass != password) { cout << "\n\nAccess Denied."; //Delays for another try Sleep(1000); menu(menuSelection); } else if(logName == userName && logPass == password) { cout << "Welcome\n\n"; //waits for user to exit system("pause"); } } else if(menuSelection == 3) { cout << "\n\nOk, Bye.\n\n"; system("pause"); } else { cout << "\n\nThats not an Option. Bye\n\n"; system("pause"); } return 0; }You have quite alot of issues here though.
1. The C++ standard says that main should take 1 of two forms:
int main();
or
int main( int argc, char* argv[] );
2. When the menu is selected and the creation of the account is made, for example, the menu is reshown but when you select it the application exits. To keep this application alive you need to do some sort of looping, until a certain option is chosen to exit the application.
3. The formatting of the code is pretty bad, but thats not so important.
I hope that helps mate,
Dave
Author
Quote:Original post by Dave
Hi bud,
Right so i have got it working here for you:
*** Source Snippet Removed ***
You have quite alot of issues here though.
1. The C++ standard says that main should take 1 of two forms:
int main();
or
int main( int argc, char* argv[] );
2. When the menu is selected and the creation of the account is made, for example, the menu is reshown but when you select it the application exits. To keep this application alive you need to do some sort of looping, until a certain option is chosen to exit the application.
3. The formatting of the code is pretty bad, but thats not so important.
I hope that helps mate,
Dave
I have a few question.
1) what does the & in the menu() do? I took it out and it didnt work properly, but then i put it back and it worked fine.
2) can you put any variable in a functions ()'s and it becomes about of that function?
ex: menu(menuSelection);
3) How was the code formatted bad? Not to be defensive, but so I can work on it and improve on that.
BTW, thanx for pointing those errors out :)
The '&' is for passing a 'reference' of the variable 'menuSelection'. This is so that the variable in main, is the same varaible in menu. So when it is changed in menu, it is also changed in main.
Author
Quote:Original post by SelethD
The '&' is for passing a 'reference' of the variable 'menuSelection'. This is so that the variable in main, is the same varaible in menu. So when it is changed in menu, it is also changed in main.
OOoOOoOoO! Thank you very much!
Im not quite sure your what your asking in your 2nd question, but I think this is what your wanting to know.
If I have a function...
void menu(int &selection)
{
do something in here
}
and a main function
void main(void)
{
int value;
}
can the variable 'value' be passed into the () of menu? yes
like so
void main(void)
{
int value;
menu(value);
}
this is valid, because the function 'menu' can have its own name for a variable, but its still the same variable thats sent to menu from main.
Does that make any sense?
If I have a function...
void menu(int &selection)
{
do something in here
}
and a main function
void main(void)
{
int value;
}
can the variable 'value' be passed into the () of menu? yes
like so
void main(void)
{
int value;
menu(value);
}
this is valid, because the function 'menu' can have its own name for a variable, but its still the same variable thats sent to menu from main.
Does that make any sense?
Author
Dude, I was trying to create something the other day, if I knew this then, I might of been successful... haha. Thanks for the help everybody.
This topic is closed to new replies.
Advertisement
Popular Topics
Advertisement
