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std::stringstream as a class member

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Started by KaelisAsur February 19, 2008 04:39 AM

4 comments, last by TheFlyingDutchman 16 years, 2 months ago

KaelisAsur

122

Author

February 19, 2008 04:39 AM

Hello there. I am having a problem with std::stringstream as a class member. I am using it in my class for conversion from int to string etc. Its pretty straightforward, really: Header:


#include <string>
#include <sstream>

//(...)

std::stringstream ss;

Source:


//(...)

ss << mNumber;
ss.str() >> this->mText;

I am getting following compile errors:

Quote: d:\hge\projects\temp\temp\digitfield.cpp(39) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::operator >>(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::basic_string<_Elem,_Traits,_Ax>' with [ _Elem=char, _Traits=std::char_traits<char>, _Ax=std::allocator<char> ] d:\programy\microsoft visual studio 8\vc\include\string(425) : see declaration of 'std::operator >>'

Kylotan

10,512

February 19, 2008 04:47 AM

What type is 'mText'?

Evil Steve

2,021

February 19, 2008 04:49 AM

std::stringstream::str() returns a std::string, and there's no operator >> that takes two std::strings.

You probably want:
this->mText = ss.str();

EDIT: Err, no, I'm talking crap.
EDIT #2: No, I was right [smile]

[Edited by - Evil Steve on February 19, 2008 5:49:06 AM]

Ashkan

451

February 19, 2008 05:02 AM

Your code doesn't work for the same reason that:

std::string x( "someString" );std::string y;y << x;// ORx >> y;

doesn't work. It actually has nothing to do with stringstreams, which I suspect is due to the fact that std::string provides no operator >>, which takes two std::string objects, but Evil Steve has already pointed that out and he thinks he's talking crap, so maybe I'm wrong after all[smile]

Try the following code instead:

std::stringstream ss;ss << mNumber;this->mText = ss.str();

KaelisAsur

122

Author

February 19, 2008 05:11 AM

Right, of course! Silly me for not noticing that.

Thanks!

TheFlyingDutchman

118

February 20, 2008 02:45 AM

Even a bit nicer (though, it depends on your needs) might be:

std::stringstream ss;ss << mNumber;// this extracts only the last string from ssss >> this->mText;

std::stringstream as a class member

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