# Rotation from 0 to 360 Degree

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nareshn2008    122
Hi I have counter range from -65536 to 65536. I am getting these counter as in this Range but i want to only show the degree 0 to 360. like if counter is 390 then it should show 30 degree . So how can i do it ?

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jeanbonours    122
First, my feeling is that your angle should be in [0, 359] range, not [0, 360]

Anyway, if I can suppose that :
* -65536 corresponds to 0,
* and 65536 corresponds to 359,

then it's a simple scaling question :
* scale down your value in the [0, 1] range,
* then multiply the scaled value by 359.

e.g.

v in [-65536, 65536]
v' = (v - (-65536))/(65536 - ((-65536))
v' = (v+65536)/(2*65536)
v'' = v' * 359

v'' is your value in the [0, 359] range.

Hope it helps

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Kalasjniekof    246
The following code is untested and probably not the best possible sollution for you problem. On the positive side: it should work!
  int c = int(counter) + 65536;  int angle = c %360;

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nareshn2008    122
Hi

Thanx for reply But there is some confusion in post.

From Counter -Value to +Value i am getting is not fixed . for example if rotate object from once from 0 to 359 and next counter will be 360 ,361,362.....and on... if i rotate in negative direction then it starting decrease to 362....360... to 0 ... -200,

So my problem is value i am getting in any range but it should be converted to 0 to 359 degree.

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Zipster    2359
Try: int angle = (counter % 360) + int(counter < 0) * 360

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nareshn2008    122
Hi

That's working fine... :)