Quote:Original post by Rich76
No, he did not write it. For your information, the senior programmer now works for Yahoo!, lol. I don't think the decompilation gives him justice, though.
Quote:Original post by phresnelQuote:Original post by Rich76
No, he did not write it. For your information, the senior programmer now works for Yahoo!, lol. I don't think the decompilation gives him justice, though.
Appearances of "lol" in phrases that are not jokes or otherwise funny somehow make me nervous. But it might just be me.
Quote:Original post by Rich76Quote:Original post by phresnelQuote:Original post by Rich76
No, he did not write it. For your information, the senior programmer now works for Yahoo!, lol. I don't think the decompilation gives him justice, though.
Appearances of "lol" in phrases that are not jokes or otherwise funny somehow make me nervous. But it might just be me.
Hmm, maybe you understood it differently. It's like hearing news Barney Fife became head of the FBI. But in any case, I'm sorry I made you feel nervous. :(
Quote:Original post by Rich76
Absolutely. I agree with you. I have been known to abuse the LOL and have said to myself, "that wasn't really funny". :)
Quote:Original post by Chrono1081Quote:Original post by Rich76
I'm a C# programmer, however, I need to figure out how to fix a C++ conditional statement for a friend. C++ conditional statements look a bit confusing to me.
Can you cast the following variable as an int in a conditional statement:
CWinThread* pThread = AfxGetThread();
int v8;
if ( (*(int (**)(int))(*(DWORD *)pThread + 80))(pThread) )
{
v8 = (*(int (**)(int))(*(DWORD *)pThread + 84))(pThread);
}
Best...code...evar...:P
Man I can't decifer that. The (**) confuses me but I'm also kind of a beginner.
Quote:Original post by Rich76
if ( (*(int (**)(int))(*(DWORD *)pThread + 80))(pThread) )
{
v8 = (*(int (**)(int))(*(DWORD *)pThread + 84))(pThread);
}
Quote:Quote:Quote:
if ( (*(int (**)(int))(*(DWORD *)pThread + 80))(pThread) )
{
v8 = (*(int (**)(int))(*(DWORD *)pThread + 84))(pThread);
}
Man I can't decifer that. The (**) confuses me but I'm also kind of a beginner.
EDIT: I mean the whole casting in general, if you mean the (**), that's a cast to a pointer to a pointer... still no idea what is being done there though o_O
int foo(int x){}// Typedefs make function pointers, and C++ in general, more manageable.typedef int (*FunctionPtr) (int);typedef FunctionPtr *FunctionPtrPtr;int main(){ // hard way int (*ptr)(int) = foo; // easy way FunctionPtr ptr = foo; // very hard way int (**ptr_to_ptr)(int) = &ptr; // easier FunctionPtrPtr ptr_to_ptr = &ptr;}Quote:Original post by DevFredQuote:Original post by Rich76
if ( (*(int (**)(int))(*(DWORD *)pThread + 80))(pThread) )
{
v8 = (*(int (**)(int))(*(DWORD *)pThread + 84))(pThread);
}
You are three weeks late for April Fool's Day.
Quote:Original post by Rich76 -- Posted - 4/21/2009 9:43:02 PM
LOL, sorry guys.
It's not his fault. He's not a programmer. This is decompiled source code. pThread is the only name change of the decompilation.
Our original source code is gone.
Quote:Original post by rip-offQuote:Quote:Quote:
if ( (*(int (**)(int))(*(DWORD *)pThread + 80))(pThread) )
{
v8 = (*(int (**)(int))(*(DWORD *)pThread + 84))(pThread);
}
Man I can't decifer that. The (**) confuses me but I'm also kind of a beginner.
EDIT: I mean the whole casting in general, if you mean the (**), that's a cast to a pointer to a pointer... still no idea what is being done there though o_O
Its not a cast to a pointer to a pointer. Look at the parentheses. It is part of the type. "int (**)(int)" is a pointer-to a pointer to a function that takes and returns an integer (or integer sized argument on this architecture).
*** Source Snippet Removed ***
I've used integers here, but given the argument passed to the function it is more likely the parameter is a pointer type. I imagine that including pointer parameters in the above would not have helped its already dubious clarity. [smile]
