You're not going to actually be expected to compute i. The sqrt(-1) is shown as i because you can't actually get a numerical value for it. That's why the professor gave you all those numbers in the form a+b*i. Think about what that operator+ overload is doing. You take 2 complex numbers, and return a double. Is that what the assignment is asking? Is that how complex numbers add together?
in the formula given its adding 2 complex numbers together isnt it?
1st complex #: a,b 2nd complex #: c->(a),d->(b) (in the formulas)
so shouldnt the math functions add, subtract etc computer those formulas?
Design a class named Complex for representing complex numbers and the functions add, subtract, multiply, divide for performing complex number operations, and the tostring function for returning a string representation for a complex number. The tostring function returns a + bi as a string. If b is 0, it simply returns a.
So should it be printing them as they were adding them together in a string instead? or computer it into a value double.
and as for i. exactly, i dont get how to compute i in any of the functions to return a double. it doesnt say what the add functions etc are supposed to do but it gives you a formula so i assumed it should return some sort of value...
Quote:Original post by RogerThat123 in the formula given its adding 2 complex numbers together isnt it?
1st complex #: a,b 2nd complex #: c->(a),d->(b) (in the formulas)
so shouldnt the math functions add, subtract etc computer those formulas?
Design a class named Complex for representing complex numbers and the functions add, subtract, multiply, divide for performing complex number operations, and the tostring function for returning a string representation for a complex number. The tostring function returns a + bi as a string. If b is 0, it simply returns a.
So should it be printing them as they were adding them together in a string instead? or computer it into a value double.
and as for i. exactly, i dont get how to compute i in any of the functions to return a double. it doesnt say what the add functions etc are supposed to do but it gives you a formula so i assumed it should return some sort of value...
It seems you're getting hung up a bit on the math part of the assignment.
You might take a look at the Wikipedia article on complex numbers, which includes a summary of the operations you've been asked to implement (I didn't look at the summary that carefully, but I assume it's correct). [Edit: Never mind - it looks like you already have that info.]
Note that in general, the result of these operations is another complex number, not a real number. That should give you a hint as to what's wrong with your current implementation, and how to fix it.
Quote:but how can I overload the + and - unary versions, i did the + and - binary already.
Implement the unary + and - operators as member functions with return type Complex. If you're not sure how to do this, just Google 'c++ operator overloading' and you should be able to find some examples.
Quote:also, when i overload ++ and -- what should it be doing? increasing the complex number by 1? how would i do that..
It's not immediately clear to me what meaning these operators would have for a complex number type. Are you sure that you're expected to implement these particular operators?
A unary operator takes one argument. A binary operator takes two.
When you write the operator overload as a member function, the this-object provides one argument, and the parameters provide the others.
Therefore, unary +, implemented as a member function, has no parameters.
This operator is used for something like 'Complex b = +a'. You read the plus as "positive". Similarly to with real numbers, where "+3" means the same thing as 3, you would implement this operator to have no effect. Thus, unary + returns a copy of the current object. If you're returning by value (as you should), then the copy is done automatically by the process of returning, so you can just "return *this;".
For unary -, also known as negation, there are again no parameters. You need to return the negative of the current value; something that, added to the current object, yields zero.
