[Solved] Multiplied colors get invisible

bo · 2010-05-05T16:01:25

Hello, I'm using the following pixel shader source. I'm setting the FragColor to the result of a multiplication between the color of a "diffuse" texture by the color of a 1D light table texture (attempting toon-shading, that is). uniform sampler1D TextureUnit0; //1D Light-table. uniform sampler2D TextureUnit1; //Diffuse texture. varying vec3 vNormal; void main() { vec3 L = normalize(vec3(gl_LightSource[0].position)); float intensity = clamp(dot(L,vNormal),0.0,1.0); vec4 value = texture1D(TextureUnit0, intensity); vec4 texel = texture2D(TextureUnit1, gl_TexCoord[0].st); gl_FragColor = value * texel; } Here's the thing: the mesh becomes completely invisible. If I comment out the "texel" variable in the line "gl_FragColor = value * texel;", the mesh becomes visible but only showing the plain lighting by the 1D texture. If I comment out the "value" variable in this same line, the mesh becomes visible with only the diffuse texture. No issue there as well. The problem lies when I multiply them. I want the 1D texture to modulate the underlying diffuse texture(s). Can someone help me with this? [Edited by - Kryzon on May 5, 2010 4:04:51 PM]

Graphics and GPU Programming Programming

Started by Kryzon May 04, 2010 10:12 AM

9 comments, last by Kryzon 13 years, 11 months ago

Kryzon

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May 05, 2010 04:01 PM

Ah, thanks a lot, that must be it - no support for 1D textures. Changed to sampler2D and it worked.

[Solved] Multiplied colors get invisible

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[Solved] Multiplied colors get invisible

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