Quote:Original post by empirical2

Quote:Original post by Blckknight118
Ok I got the program to add every 5 times using this code:
while(crud_days % 5 != 0 && crud_days % 5 != 1)

When I asked you how many growths there would be in 30 days, is that how you worked it out in your head?

How did you get 6 from 30?

Quote:I really don't understand Fibonacci's numbers though I used this formula and it didn't work.

Your original code was closer.

I suggest you wiki Fibonacci's numbers, you cannot tell the computer how to do it, until you understand them yourself.

Quote:Original post by Blckknight118

For the growth, I simply divided by 5....

        for(int i = 1; i <= crud_days; i++)    {        do{            amount_crud = amount_crud + amount_crud;            numberof_crud = amount_crud;        }        while(crud_days % 5 == 0);	}return numberof_crud;}

Quote:My original code was closer....Ok thanks

Quote:Original post by empirical2

Quote:Original post by Blckknight118

For the growth, I simply divided by 5....

Right!. So if you wanted your function to use the formula once for every 5 days....how would you do that?

Lets look at the loop
*** Source Snippet Removed ***

Here you have two loops, and you run through a loop (the 'for' loop) that iterates once for EVERY day...but... don't we want to only do it once for every five days? Can that for loop be made to loop only once for every five days?

And if we can make the for loop only once for every 5 days......do we actually need that other do-while loop at all? ;)

Quote:My original code was closer....Ok thanks

I'm sorry, I don't really know what help to give other than the answer and that is not permitted.

However I will hint that it will require an additional variable because the order you do each part of the calculation is very important.

But i have to go to bed now as its 4am! I wish you the very best of luck :)

Quote:Original post by Erik Rufelt
Never give up. =)

Do you know how integer division works?
You can use integer division to find out how many times the crud grows. For example:
29 days: growths = 29 / 5 = 5
30 days: growths = 30 / 5 = 6
31 days: growths = 31 / 5 = 6
32 days: growths = 32 / 5 = 6
33 days: growths = 33 / 5 = 6
34 days: growths = 34 / 5 = 6
35 days: growths = 35 / 5 = 7

ints always use integer division, so you can do:
int growths = crud_days / 5;

Then you know how many times it grows.

Don't try to solve the whole thing at the same time. Start by writing two simpler programs, one that only calculates how many times the crud grows, and one that only calculates the Fibonacci sequence. Then when both these work perfectly, you can work on combining them.