How long is this line?
Author
I'm going to use this when making some strange texture effects and i need a way to find out how long a line is in an object like that one posted under this text:.
If i have one of theese:
.100.pixels.
....._____....
.../.........\...
../~~~~~\.. <---
./________\.
.200.pixels.
How can i find out how long the "~" line is in pixels if i know hot far away the "~" line is away from one of the sides? Maby this don't make any sense but i'm not that good at english...
Can you help me?
[edited by - Andos on April 18, 2002 11:23:49 AM]
[edited by - Andos on April 18, 2002 11:24:09 AM]
[edited by - Andos on April 18, 2002 11:24:25 AM]
Find the angle and use trig function to find the position of the intersection between the / and \ lines and the ~~~ line.
Then, find the distance between those two points.
Out of curiosity, what are you doing?
----------------
Blaster
Computer game programmer and part time human being
Strategy First - http://www.strategyfirst.com
BlasterSoft - http://www.blastersoft.com
Then, find the distance between those two points.
Out of curiosity, what are you doing?
----------------
Blaster
Computer game programmer and part time human being
Strategy First - http://www.strategyfirst.com
BlasterSoft - http://www.blastersoft.com
Author
Can''t this be used?:
LengthLine1-(((LengthLine1 - LengthLine2) / 100 ) * ( ( YofLine / DistanceBetweenLine1&2) * 100 ))
I''m trying to make a wierd software texture rendering...
LengthLine1-(((LengthLine1 - LengthLine2) / 100 ) * ( ( YofLine / DistanceBetweenLine1&2) * 100 ))
I''m trying to make a wierd software texture rendering...
L = (L2-L1)*t + L1 where t goes from zero (L1) to one (L2).
In your case t = Y/distance(L1,L2)
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Stolen from Magmai Kai Holmlor, who held it from Oluseyi, who was inspired by Kylotan...
[edited by - Fruny on April 18, 2002 2:20:25 PM]
In your case t = Y/distance(L1,L2)
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[Docs (RTFM) | MSDN | SGI's STL | OpenGL | File formats]
[C++ Must Haves (RTFS) | MinGW | Boost | Loki | FLTK | SDL ]
Stolen from Magmai Kai Holmlor, who held it from Oluseyi, who was inspired by Kylotan...
[edited by - Fruny on April 18, 2002 2:20:25 PM]
Author
You mean:
L: Length of the line I try to find
L1: Line 1
L2: Line 2
t: Y or X / with the distance between L1 & L2
Is this correct?
L: Length of the line I try to find
L1: Line 1
L2: Line 2
t: Y or X / with the distance between L1 & L2
Is this correct?
Yup, that''s called linear interpolation.
[Questions (STFW) | GDNet Start Here | GDNet Search | Forum FAQ | Google | Asking Smart Questions ]
[Docs (RTFM) | MSDN | SGI''s STL | OpenGL | File formats]
[C++ Must Haves (RTFS) | MinGW | Boost | Loki | FLTK | SDL ]
Stolen from Magmai Kai Holmlor, who held it from Oluseyi, who was inspired by Kylotan...
[Questions (STFW) | GDNet Start Here | GDNet Search | Forum FAQ | Google | Asking Smart Questions ]
[Docs (RTFM) | MSDN | SGI''s STL | OpenGL | File formats]
[C++ Must Haves (RTFS) | MinGW | Boost | Loki | FLTK | SDL ]
Stolen from Magmai Kai Holmlor, who held it from Oluseyi, who was inspired by Kylotan...
Author
But can my other formula also be used?
In code it would maby look like this:
float
LengthLine1, LengthLine2, LENGTHOFUNKNOWNLINE
float
YofUnknownLengthLine, Distance, difference
float
YofLine1, YofLine2
//finish floating ;-)
Start loop
LengthLine1=200
LengthLine2=100
YofLine1=0
YofLine2=100
YofUnknownLengthLine=50
Diffecence=LengthLine1 - LengthLine2
Distance= YofLine2 - YofLine1
LENGTHOFUNKNOWNLINE= LengthLine1-((difference/100)*((YofUnknownLine / distance)*100))
stop loop
In code it would maby look like this:
float
LengthLine1, LengthLine2, LENGTHOFUNKNOWNLINE
float
YofUnknownLengthLine, Distance, difference
float
YofLine1, YofLine2
//finish floating ;-)
Start loop
LengthLine1=200
LengthLine2=100
YofLine1=0
YofLine2=100
YofUnknownLengthLine=50
Diffecence=LengthLine1 - LengthLine2
Distance= YofLine2 - YofLine1
LENGTHOFUNKNOWNLINE= LengthLine1-((difference/100)*((YofUnknownLine / distance)*100))
stop loop
((Base - Top) * .5) + Top
That should do it. Assuming that the "~" line is half the distance between the top and bottom.
I sure hope this world isn't one big joke, because I don't get it.
[edited by - VisualB4BigD on April 21, 2002 5:16:54 AM]
That should do it. Assuming that the "~" line is half the distance between the top and bottom.
I sure hope this world isn't one big joke, because I don't get it.
[edited by - VisualB4BigD on April 21, 2002 5:16:54 AM]
Simply speaking, find the equation for each line, the height off the base, and plug in that value to each line equations to get the point on each line. Like someone said, linear interpolation.
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