I have a struct with a function pointer in it. This compiles fine:
typedef struct gx_quadpatch_s
{
gx_vbuffer_t* vb;
struct gx_quadpatch_s* children[4];
struct gx_quadpatch_s* parent;
//...
void (*detailer)(struct gx_quadpatch_s* dest, struct gx_quadpatch_s* source, int a_start, int a_end, int b_start, int b_end);
} gx_quadpatch_t ;
I wanted a pretty typedef for the function type:
typedef void (*gx_quadpatch_detailer_f)( struct gx_quadpatch_s* dest, struct gx_quadpatch_s* source, int a_start, int a_end, int b_start, int b_end);
typedef struct gx_quadpatch_s
{
gx_vbuffer_t* vb;
struct gx_quadpatch_s* children[4];
struct gx_quadpatch_s* parent;
//...
gx_quadpatch_detailer_f detailer;
} gx_quadpatch_t ;GCC gives this warning:
In file included from gx_quadpatch.c:18:0:
../graphics/gx_quadpatch.h:5:80: warning: 'struct gx_quadpatch_s' declared inside parameter list [enabled by default]
typedef void (*gx_quadpatch_detailer_f)( struct gx_quadpatch_s* dest, struct gx_quadpatch_s* source, int a_start, int a_end, int b_start, int b_end);
^
../graphics/gx_quadpatch.h:5:80: warning: its scope is only this definition or declaration, which is probably not what you want [enabled by default]This suggests I need to declare the struct quadpatch_s definition before the gx_quadpatch_detailer_f. Circular dependency. Not sure how to break it.
Usually if I have an interdependency between structs, I can do this:
typedef struct foo_s
{
struct bar_s* my_bar;
} foo_t;
typedef struct bar_s
{
struct foo_s* my_foo;
} bar_t;
After that, I can refer them at foo_t and bar_t. In its allowed for a struct to defined as containing a pointer to another struct that hasn't yet because all struct pointers are the same size. Can I not do the same thing with function argument lists?
Is there something I can put above the gx_quadpatch_detailer_f typedef to resolve this?
