Finding 3D co-ordinates of UV(1,1)?

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10 comments, last by Pragma 13 years, 11 months ago
That matrix is perfect.

vertex 4 {
-55.1937 -10.6140 -129.7729 ... for UV(0,0)
55.1937 -129.5679 -12.8772 ...for UV(1,0)
-55.1937 129.5679 12.8772 ...for UV(0,1) EDIT: got these 2
55.1937 10.6140 129.7729 ...for UV(1,1) UV's mixed up. Corrected.
}

Mistake was not applying the + - + matrix before the transpose. And did BxA instead of AxB.
REALLY BIG THANKS for that method and spending the time to go through explaining it and checking the answers.

Very very appreciated, not only by me but the hundreds of others who will be using it as well.

[Edited by - SNARG on May 9, 2010 11:32:03 PM]
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You're welcome, glad you found it useful.
"Math is hard" -Barbie

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