quote:Original post by Arild Fines
Using void to indicate an empty parameter list is not recommended in C++.

int SomeFunc(void) { ... }; 

quote:
Can I write "void main()"?
The definition
void main() { /* ... */ }

is not and never has been C++, nor has it even been C. See the ISO C++ standard 3.6.1[2] or the ISO C standard 5.1.2.2.1. A conforming implementation accepts
int main() { /* ... */ }

and
int main(int argc, char* argv[]) { /* ... */ }

A conforming implementation may provide more versions of main(), but they must all have return type int. The int returned by main() is a way for a program to return a value to "the system" that invokes it. On systems that doesn''t provide such a facility the return value is ignored, but that doesn''t make "void main()" legal C++ or legal C. Even if your compiler accepts "void main()" avoid it, or risk being considered ignorant by C and C++ programmers.
In C++ main() need not contain an explicit return statement. In that case, the value returned is 0, meaning successful execution. For example:

#include

int main()
{
std::cout << "This program returns the integer value 0\n";
}

Note also that neither ISO C++ nor C99 allows you to leave the type out of a declation. That is, in contrast to C89 and ARM C++ ,"int" is not assumed where a type is missing in a declaration. Consequently:
#include

main() { /* ... */ }

is an error because the return type of main() is missing.